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30m^2-41m=0
a = 30; b = -41; c = 0;
Δ = b2-4ac
Δ = -412-4·30·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-41}{2*30}=\frac{0}{60} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+41}{2*30}=\frac{82}{60} =1+11/30 $
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